3k^2-3k-126=0

Solution for 3k^2-3k-126=0 equation:

3k^2-3k-126=0

a = 3; b = -3; c = -126;
Δ = b2-4ac
Δ = -32-4·3·(-126)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-39}{2*3}=\frac{-36}{6}
=-6
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+39}{2*3}=\frac{42}{6}
=7
$